25y^2+10y-80=0

Solution for 25y^2+10y-80=0 equation:

25y^2+10y-80=0

a = 25; b = 10; c = -80;
Δ = b2-4ac
Δ = 102-4·25·(-80)
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8100}=90$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-90}{2*25}=\frac{-100}{50}
=-2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+90}{2*25}=\frac{80}{50}
=1+3/5
$